Am trying to import excel file. From current state I can upload the file, But I want insert excel file on each different table depending on the values in the combo box. ie if Value is A insert into tableA,Value is B insert into tableB like that. Am looking for, is it possible to check the values in the route and call model function.
Blade file
<form id="ExcelImportForm" method="post" enctype="multipart/form-data" action="">
<table class="table">
<tr>
<td>Select Project *</td>
<td>
<select required class="form-control" name="ExcelProject" id="ExcelProject">
<option selected disabled>Select Technology</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
<option value="D">D</option>
</select>
</td>
</tr>
<tr>
<td>Select File *</td>
<td><input class="form-control" type="file" id="file" name="file" required ></td>
</tr>
<tr>
<td></td>
<td><button type="submit" id="ExcelMasterBtn" class="btn btn-success pull-right"><i class="fa fa-upload"></i> Upload</button></td>
</tr>
</table>
</form>
Below give is route which is working in single case, is it possible to implement an if statement inside that.
route.php
Route::get('/upload-panel/', function () {
(new \App\Http\Model\Excelentry())->importToDb();
return view('admin.upload-panel.excel-upload-panel');
});
Or anyother way to get this combobox value inside the model function
via Chebli Mohamed
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