I have this project that when a user clicks on a button the data should be displayed on a table. However, I am using a table as shown here. What I want is that when a user clicks on the add button on the enrollment form table, it should displayed on the added subjects table without the need of refreshing the page. The problem is that I am using a table and I cannot make use of the v-model to bind the values.
So here's my form.blade.php
Enrollment Form table
<table class="table table-bordered">
<tr>
<th>Section</th>
<th>Subject Code</th>
<th>Descriptive Title</th>
<th>Schedule</th>
<th>No. of Units</th>
<th>Room</th>
<th>Action</th>
</tr>
<body>
<input type="hidden" name="student_id" value="">
@foreach($subjects as $subject)
@foreach($subject->sections as $section)
<tr>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td>
<button
v-on:click="addSubject( , )"
class="btn btn-xs btn-primary">Add
</button>
<button class="btn btn-xs btn-info">Edit</button>
</td>
</tr>
@endforeach
@endforeach
</body>
</table>
AddedSubjects Table
<table class="table table-bordered">
<tr>
<th>Section Code</th>
<th>Subject Code</th>
<th>Descriptive Title</th>
<th>Schedule</th>
<th>No. of Units</th>
<th>Room</th>
<th>Action</th>
</tr>
<body>
<tr v-for="reservation in reservations">
<td>@</td>
<td>@</td>
<td>@</td>
<td>@</td>
<td>@</td>
<td>@</td>
<td>
<button class="btn btn-xs btn-danger">Delete</button>
</td>
</tr>
</body>
</table>
And here's my all.js
new Vue({
el: '#app-layout',
data: {
reservations: []
},
ready: function(){
this.fetchSubjects();
},
methods:{
fetchSubjects: function(){
this.$http({
url: 'http://localhost:8000/reservation',
method: 'GET'
}).then(function (reservations){
this.$set('reservations', reservations.data);
console.log('success');
}, function (response){
console.log('failed');
});
},
addSubject: function(id,student_id){
this.$http({
url: 'http://localhost:8000/reservation',
data: { sectionSubjectId: id, studentId: student_id },
method: 'POST'
}).then(function(response) {
console.log(response);
},function (response){
console.log('failed');
});
}
}
});
Can anyone suggets me on how to solve this problem, without the need of refreshing the page.
via Chebli Mohamed
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